limjunyoung

级别: 荣誉会员 一等解题奖
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注册时间:2006-04-26
最后登陆:2008-10-11
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Sn=(n^2+2n)Π/3,求cos^2An+1+cos^2An+cos^2An-1 Sn-Sn-1=An=Π/3(2n-1+2)=(2n+1)Π/3=2nΠ/3+Π/3 cos^2An+1+cos^2An+cos^2An-1 n=3k cos^2An+1+cos^2An+cos^2An-1=1/4+1/4+1/4=3/4 n<>3k cos^2An+1+cos^2An+cos^2An-1=1/4+1/4=1/2
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